(3x+2)(7x-4)=21x^2+10

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Solution for (3x+2)(7x-4)=21x^2+10 equation:


Simplifying
(3x + 2)(7x + -4) = 21x2 + 10

Reorder the terms:
(2 + 3x)(7x + -4) = 21x2 + 10

Reorder the terms:
(2 + 3x)(-4 + 7x) = 21x2 + 10

Multiply (2 + 3x) * (-4 + 7x)
(2(-4 + 7x) + 3x * (-4 + 7x)) = 21x2 + 10
((-4 * 2 + 7x * 2) + 3x * (-4 + 7x)) = 21x2 + 10
((-8 + 14x) + 3x * (-4 + 7x)) = 21x2 + 10
(-8 + 14x + (-4 * 3x + 7x * 3x)) = 21x2 + 10
(-8 + 14x + (-12x + 21x2)) = 21x2 + 10

Combine like terms: 14x + -12x = 2x
(-8 + 2x + 21x2) = 21x2 + 10

Reorder the terms:
-8 + 2x + 21x2 = 10 + 21x2

Add '-21x2' to each side of the equation.
-8 + 2x + 21x2 + -21x2 = 10 + 21x2 + -21x2

Combine like terms: 21x2 + -21x2 = 0
-8 + 2x + 0 = 10 + 21x2 + -21x2
-8 + 2x = 10 + 21x2 + -21x2

Combine like terms: 21x2 + -21x2 = 0
-8 + 2x = 10 + 0
-8 + 2x = 10

Solving
-8 + 2x = 10

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 2x = 10 + 8

Combine like terms: -8 + 8 = 0
0 + 2x = 10 + 8
2x = 10 + 8

Combine like terms: 10 + 8 = 18
2x = 18

Divide each side by '2'.
x = 9

Simplifying
x = 9

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